2sin^2(x)+3cos(x)=1

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Solution for 2sin^2(x)+3cos(x)=1 equation: 


Simplifying
2sin2(x) + 3cos(x) = 1

Multiply in2s * x
2in2sx + 3cos(x) = 1

Multiply cos * x
2in2sx + 3cosx = 1

Reorder the terms:
3cosx + 2in2sx = 1

Solving
3cosx + 2in2sx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sx' to each side of the equation.
3cosx + 2in2sx + -2in2sx = 1 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
3cosx + 0 = 1 + -2in2sx
3cosx = 1 + -2in2sx

Divide each side by '3osx'.
c = 0.3333333333o-1s-1x-1 + -0.6666666667in2o-1

Simplifying
c = 0.3333333333o-1s-1x-1 + -0.6666666667in2o-1

Reorder the terms:
c = -0.6666666667in2o-1 + 0.3333333333o-1s-1x-1

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